574.
575.
563.P2 = (1-r1) × (1-r2) = (1 - 1/2) × (1 - 1/2) = 1/4 = 0.25;
P3 = (1-r1) × (1-r2) × (1-r3) = (1 - 1/2) × (1 - 1/2) × (1 - 1/2) = 1/8 = 0.125;
P4 = (1-r1) × (1-r2) × (1-r3) × (1-r3) = (1 - 1/2) × (1 - 1/2) × (1 - 1/2) × (1 - 1/2) = 1/16 = 0.0625,...:
564.
565.
566.r1 + r2 + r3 + r4 + ... = ∞will completely fill the terminal volume, i.e., P = P∞ = 1/2 × (1-1/2)∞ = 0:
570.
571.
572.
573.
563.
567.
568.
569.
S1 = 0.5.That is, the remaining volume, P, for this series becomes zero.
S2 = 0.83333....
S3 = 1.08333....
S4 = 1.28333....
S5 = 1.5
S50 = 4.99205....
S500 = 6.79282....
S5,000 = 9.09451....
S50,000 = 11.39700....
S500,000 = 13.69958....
557.
556.
170.
1.1. Skin is the largest organ, by volume or by weight, of the body.There are one million new diagnoses of skin cancer annually in the USA, more than all other body-sites combined. The big four, besides skin, are: colon, breast, prostate, lung, all on the order of 100,000 new cases annually in the USA, and all predominantly epithelial (surface) tumors. Non-surface tumors (hematolymphatic, bone, and soft-tissue) are all comparatively uncommon. Extrapolating, based upon the world having 20x the population of the USA, then there are at least 20 million new surface-cancer cases annually in the world.
1.2. Skin is most exposed to environmental insults.
1.3. Skin growths are most easily recognized, and come early to medical attention.
Pn = (1-r1)(1-r2)(1-r3) ... (1-rn), for n = 1, 2, 3, ....In the model Pn represents the proportion of terminal volume remaining after the nth papilla has entered the terminal volume. Then the sequence of numbers, Pn, is decreasing with increasing n; and the Pn possess a limit, P, as n → ∞, lying between 0 and 1, or possibly at 0 itself. P is called the infinite product, and is written:
P = P∞ (1-r1)(1-r2)(1-r3) ...The obvious question to ask is: Does P=0 or is P>0? A related question to ask is: What is the limit, S, of the increasing sequence of partial sums:
Sn = r1 + r2 + r3 + ... + rn.of the same numbers, as n⇒∞? Does S=∞ or is S<∞? S is called the corresponding infinite series, and is written:
S = r1 + r2 + r3 + ....It is shown that P is sandwiched ("STRUBLE SANDWICH") in between two decaying exponential functions of S:
a-S < P < e-S
301.(1 - R)x/R < 1-xholds for all x, 0 < x < R, as shown in the graph:
302.(1) for x=0, (1-R)0 = (1-0) = 1;Exponentiating both sides by x yields:
(2) for x=R, (1-R)1 = (1-R); and
(3) for x=0,
(1 - R)x/R < 1-xQ.E.D.
(1-R)(1/R)rk < 1 - rkholds for all k, so that:
(1-R)(1/R)(r1 + r2 + r3 + ... rn) < (1-r1)(1-r2)(1-r3) ... (1-rn) = Pnholds for all n, and:
(1-R)(1/R)S < P.It is useful to recast this inequality in the form:
L = a-S < P < e-S = U,where a = 1/(1-R)(1/R) > e. Therefore, P is sandwiched between two decaying exponential functions of S:
L = a-S < P < e-S = U,It can be shown that the sandwiching is tight if R is small []. In any event, P > 0 if S < ∞.
29.
44.∫-π+π h(x) dx (Riemann notation) = ∫[-π,+π] (Lebesgue notation) = π
F(x) = ∑n=0n=∞ an sin nx + bn cos nx.where F(x) can be used to fit any function ARBITRARILY CLOSELY, over a finite interval. The customary domain interval for discussing a Fourier series is [-π,+π], i.e., the interval from -π to +π, although the Fourier series domain may be scaled upward or downward, to any desired interval. The customary range of the Fourier series is [-1,+1], but again, this range may be scaled. The issue of what is meant by "arbitrarily closely" is the subject of MEASURE THEORY.
http://mathworld.wolfram.com/RiemannIntegral.htmlstates baldly that Lebesgue integration is purely a mathematical fairy-tale; that there is no function in nature whose area cannot be determined by Riemann integration. The pundit is right, but he misses an important point. Yes, the Heaviside function is obviously R-integrable over any interval, certainly without resorting to Fourier-series; whereas Cantor's interval-function arose exclusively in Cantor's addled brain, and certainly exists nowhere else in nature. On the other hand, Fourier-series is an incredibly powerful tool in applied mathematics, that curve-fits everything from planetary orbits to pathology images. Why abandon Fourier series? Why not have a general theory of integration that includes Fourier series in its toolbox, especially since L=R whenever R exists, anyway? Why not spend a few more weeks in your mathematics course, learning about Lebesgue integration?
P = (1/2)(3/4)(7/8) ... (2n-1)/(2n) e(2n-1)/(2n)
= 0.2887881
1/(1-x) = 1 + x + x2 + x3 + ...This can be verified by multiplying both sides of the equation by (1-x). Therefore, 2 = 1/(1 - 1/2) = 1 + 1/2 + 1/4 + 1/8 + .... Subtracting 1 from both sides of the equation yields: 1 = 1/2 + 1/4 + 1/8 + .... Q.E.D.
1/2 < 1/2,Since 1/2 + 1/2 + 1/2 + 1/2 + ... = ∞, the harmonic series is divergent. Q.E.D.
1/3 + 1/4 < 1/2,
1/5 + 1/6 + 1/7 + 1/8 < 1/2,
1/9 + 1/10 + 1/11 + 1/12 + 1/13 + 1/14 + 1/15 + 1/16 < 1/2,
#/usr/local/bin/perl
$iii=0; $hhh=0; $dnm=1;
$head=1; $tail=2.718281828;
while($iii<25){$iii++;
$tail=sqrt($tail);
$dnm=$dnm*2; $num=$dnm-1;
$head=$head*($num/$dnm);
$hhh = $head*$tail;
print "\n $iii h = $hhh";};
exit;